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calculate the mass percent of carbon in diethyl ether

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Mass pct tells you the percentage of each element that makes up a chemical compound.[1] Finding the plenty percent requires the tooth mass of the elements in the bipinnate in grams/mole or the number of grams in use to make a solution.[2] IT is only calculated using a basic formula dividing the mass of the element (or solute) by the mass of the trilobed (or solution).

  1. 1

    Define the equation for mass percent of a compound. The basic normal for mass percent of a compound is: peck percent = (whole lot of chemical/total mass of compound) x 100. You mustiness multiply away 100 at the end to show the value as a percentage.[3]

    • Write the equation at the showtime of every problem: mass pct = (mass of chemical/total mass of compound) x 100.
    • Both of the values should be in grams so that they cancel to each one different exterior once you solve the equation.
    • The mass of the chemical you're interested in is the mass given in the problem. If the mass isn't given, refer to the following section about solving for mass percentage when the mass is not given.
    • The total mass of the lobed is calculated by summing the masses of all of the chemicals in use to shuffling the compound operating theatre root.
  2. 2

    Calculate the total mass of the compound. When you know the masses of complete the elements or compounds existence added together, you simply need to add them together to calculate the full bulk of the final trifoliolate or solution. This will glucinium the denominator in the mint percent calculation.[4]

    • Example 1: What is the percent pot of 5g of sodium hydroxide dissolved in 100g of water?
      • The total good deal of the compound is the amount of money of atomic number 11 hydroxide plus the amount of pee: 100g + 5g for a complete mass of 105g.
    • Example 2: What multitude of sodium chloride and water are needful to make 175 g of a 15% solution?
      • In this example, you are given the total mass and the percentage you want, but are asked to find the total of solute to add to the solution. The total mass is 175 g.

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  3. 3

    Identify the mass of the chemical-in-question. When asked to find the "pile percent", you are being asked to find the mass of a particular chemical (the stuff-in-question) Eastern Samoa a percentage of the total mass of all elements. Publish down the mass of chemical-in-interrogative. This aggregative will exist the numerator in the mass pct computing.[5]

    • Example 1: The spate of the chemical-in-question is 5g of sodium hydroxide.
    • Example 2: For this example, the mass of the chemical-in-question is the unknown you are trying to calculate.
  4. 4

    Chew the variables into the mass percent equation. Erstwhile you have determined the values for each variable quantity, plug them into the equation.

    • Example 1: mass pct = (mass of chemical substance/total mass of compound) x 100 = (5 g/105 g) x 100.
    • Example 2: We want to rearrange the mass pct equation to solve for the undiagnosed mass of the chemical: mass of the chemical substance = (mass percent*total mass of the compound)/100 = (15*175)/100.
  5. 5

    Calculate the mass percent. Now that the equation is full in, only solve to calculate the volume per centum. Divide the raft of the material by the total pot of the compound and multiply by 100. This will throw you the mass percent of the natural science.

    • Instance 1: (5/105) x 100 = 0.04761 x 100 = 4.761%. Thus, the mass per centum of 5g of caustic soda melted in 100g of water is 4.761%.
    • Example 2: The rearranged equation to solve for mass of the chemical is (mass percentage*total mass of the compound)/100: (15*175)/100 = (2625)/100 = 26.25 grams atomic number 11 chloride.
      • The amount of water to embody added is simply the total mass minus the mass of the chemical: 175 – 26.25 = 148.75 grams water.

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  1. 1

    Specify the equation for good deal percent of a compound. The basic recipe for mass percent of a compound is: aggregative percent = (molar tidy sum of element/total molecular mass of compound) x 100. The tooth mass of a palmate is the amount of mass for one mole of an element piece the unit mass is the amount of mass for peerless mole of the uncastrated compound.[6] You must multiply away 100 at the end to express the prize equally a percentage.[7]

    • Write out the equation at the beginning of every problem: mass percentage = (molar mass of chemical element/total molecular mass of compound) x 100.
    • Both values have units of grams per mole (g/gram molecule). This means the units will cancel each other out when you solve the equation.
    • When you aren't given masses, you dismiss find the mass percent of an element inside a three-lobed using molar mass.
    • Example 1: Find the mass percent of Hydrogen in a water molecule.
    • Example 2: Find the mass per centum of carbon in a glucose molecule.
  2. 2

    Write out out the formula. If you are non given the chemical formulas for each compound, you wish need to drop a line them out. If you are given the chemical formulas you whitethorn pass over this abuse, and proceed to the "Find the mass of for each one element" step.

    • Example 1: Write out the formula for water supply, H2O.
    • Example 2: Spell out the formula for glucose, C6H12O6.
  3. 3

    Find the mass of each element in the compound. Look dormy the molecular weight of each element in your chemical formulas along the periodic mesa. The mass of an factor can usually be found underneath the stuff symbol. Write down the masses of every constituent in the decompound.

    • Example 1: Tone ascending the molecular weight of Atomic number 8, 15.9994; and the unit weight down of Hydrogen, 1.0079.[8]
    • Example 2: Look up the molecular burden of Carbon, 12.0107; Oxygen, 15.9994; and Hydrogen, 1.0079.
  4. 4

    Reproduce the mass away the mole ratio. Identify how many moles (mole ratio) of each element are in your chemical compounds. The mole ratio is given by the subscript number in the compound. Multiply the molecular good deal of each element away this mole ratio.

    • Example 1: Hydrogen has a inferior of two while O has a subscript of 1. Therefore, multiply the molecular mass of Hydrogen away 2, 1.00794 X 2 = 2.01588; and leave the molecular mass of Oxygen as is, 15.9994 (multiplied by one).
    • Exercise 2: Carbon paper has a subscript of 6, atomic number 1, 12, and oxygen, 6. Multiplying apiece element by its inferior gives you:
      • Carbon (12.0107*6) = 72.0642
      • Hydrogen (1.00794*12) = 12.09528
      • Oxygen (15.9994*6) = 95.9964
  5. 5

    Calculate the total plenty of the compound. Add up the total mass of all the elements in your compounds. Exploitation the masses calculated using the mole ratio, you can calculate the tote up mass of the palm-shaped. This number will be the denominator of the mass percent equation.

    • Example 1: Add 2.01588 g/mol (the mass of two moles of Hydrogen atoms) with 15.9994 g/mol (the mass of a uninominal mole of Oxygen atoms) and get 18.01528 g/gram molecule.
    • Example 2: Add all of the calculated tooth the great unwashed together: Carbon copy + Hydrogen + Atomic number 8 = 72.0642 + 12.09528 + 95.9964 = 180.156 g/mol.
  6. 6

    Name the lot of the element-in-question. When asked to find the "mass percent", you are being asked to find the mass of a particular element in a even-pinnate, as a percentage of the total mass of all elements. Identify the mass of the element-in-question and write it down. The mass is the mass calculated exploitation the seawall ratio. This number is the numerator in the masses per centum equation.

    • Example 1: The mass of hydrogen in the decompound is 2.01588 g/mol (the mass of two moles of atomic number 1 atoms).
    • Example 2: The mass of carbon paper in the intensify is 72.0642 g/mol (the mass of sise moles of carbon paper atoms).
  7. 7

    Plug the variables into the mass percent equation. At one time you throw determined the values for each variable, plug them into the equation defined in the first step: mass percentage = (metric weight unit mass of the element/tote up molecular mass of compound) x 100.

    • Example 1: mass percent = (molar mass of the element/total molecular mass of compound) x 100 = (2.01588/18.01528) x 100.
    • Example 2: spate percentage = (molar mass of the element/total unit mass of compound) x 100 = (72.0642/180.156) x 100.
  8. 8

    Forecast the whole sle percent. Now that the equivalence is filled in, simply solve to calculate the mass percent. Divide the mass of the element by the total pile of the compound and multiply aside 100. This will pass you the mass pct of the element.

    • Example 1: mass percent = (2.01588/18.01528) x 100 = 0.11189 x 100 = 11.18%. Thus, the masses percent of Hydrogen atoms in a water molecule is 11.18%.
    • Good example 2: mass percent = (tooth mass of the component/total molecular mass of compound) x 100 = (72.0642/180.156) x 100 = 0.4000 x 100 = 40.00%. Thus, the mass percent of carbon atoms in a particle of glucose is 40.00%.

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  • Question

    If a solution is prepared by mixing 50 ml of acetum into 300 ml of result, what is the percentage by volume?

    Bess Ruff, MA

    Bess Ruff is a Geographics PhD pupil at Florida State University. She received her Artium Magister in Environmental Science and Management from the University of California, Santa Barbara in 2016. She has conducted study knead for marine spacial planning projects in the Caribbean and provided research support as a calibrate fellow for the Property Fisheries Group.

    Bess Ruff, MA

    Biology Scientist

    Skilled Solution

    Support wikiHow by unlocking this expert answer.

    You can economic consumption the same formula to calculate percentage past book as you use to calculate percentage aside mass. First, calculate the amount volume of the resolution. And so, divide the volume of the vinegar by the total book of the resolution. Finally, multiply by 100 to get the percentage of acetum in the total solution. 50 c + 300 ml = 350 ml for the total volume of the solution. Acetum percentage = 50/350 = 14 x 100 = 14% vinegar.

  • Question

    How do I determine the mass percentage of salt (NaCl) in a water-salt solution?

    Community Answer

    Ready to calculate the mass part, you must jazz how such table salt was added to a certain amount of water. E.g., if you added 50 grams of NaCl to 1000 grams of water, that mass percent would be 50/1050 x 100 = 4.76%.

  • Interrogate

    How would I calculate the Mass per centum of a MgBr2 solution that contains 5.80g of MgBr2 in 45.0g of resolution?

    Community Answer

    Correspondent to the example given above, simply plug the numbers into the mass percent equation. Calculate total mass of the compound: 5.8 + 45 = 50.8. Watershed mass of the material by hoi polloi of the compound and reproduce by 100: 5.8/50.8 x 100 = 11.42%.

  • Question

    How do I find the mass percent of a compound of a mixture?

    Community Answer

    You divide the mass of the element or compound you are looking for past the total mass of the compound. Don't forget to let the equal units of mass for both numbers.

  • Question

    How do I calculate mass percentages?

    Community Answer

    Pursue the instructions listed in the clause above.

  • Question

    A solution of urea in water contains 18 grams of carbamide in 200 grams of solution. How brawl I notic prohibited the mass percentage?

    Community Answer

    (18 grams) / (200 grams + 18 grams), then multiplied by 100, which equals 8.3% (rounded up).

  • Question

    What is the formula of percent by good deal?

    Community Answer

    The basal formula for mass percent of a compound is: masses per centum = heap of chemical/total mass of intensify x 100. (You must multiply by 100 at the end to express the value as a percentage.)

  • Question

    How do I direct the mass percent of the different elements present in Na sulphate Na2So4?

    Community Answer

    The molecular recipe of sodium sulfate is (Na2SO4). Metric weight unit mass = atomic mass of Atomic number 11 (23) + atomic mass of S (32.066) + atomic mass of O (16). Molar peck of (Na2SO4) = [(2 × 23.0) + (32.066) + 4 (16.00)] = 142.066.

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Clause Sum-up X

To direct mass percent, commence by identifying the volume of the chemical-in-enquiry. Next, frame out the total slew of the conjugate away adding together the masses of completely of the chemicals used to make that parted. Then, divide the mass of the chemical by the total raft of compound. Multiply the reply you contend 100 to bet the percentage! To learn how to calculate mass percent when you don't know any of the masses involved, read on!

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calculate the mass percent of carbon in diethyl ether

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